3y^2+20y-32=0

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Solution for 3y^2+20y-32=0 equation:


Simplifying
3y2 + 20y + -32 = 0

Reorder the terms:
-32 + 20y + 3y2 = 0

Solving
-32 + 20y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-8 + -1y)(4 + -3y) = 0

Subproblem 1

Set the factor '(-8 + -1y)' equal to zero and attempt to solve: Simplifying -8 + -1y = 0 Solving -8 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1y = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1y = 0 + 8 -1y = 0 + 8 Combine like terms: 0 + 8 = 8 -1y = 8 Divide each side by '-1'. y = -8 Simplifying y = -8

Subproblem 2

Set the factor '(4 + -3y)' equal to zero and attempt to solve: Simplifying 4 + -3y = 0 Solving 4 + -3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -3y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -3y = 0 + -4 -3y = 0 + -4 Combine like terms: 0 + -4 = -4 -3y = -4 Divide each side by '-3'. y = 1.333333333 Simplifying y = 1.333333333

Solution

y = {-8, 1.333333333}

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